Parameterized curves, regularity, and reparameterization
Objective: Can two maps with the same trace define different parameterized curves?
A curve is a map, not merely its traced point set; regularity ensures a nonzero tangent direction and an admissible parameter change preserves geometric motion.
Objects and notation: A C^k curve is a map γ:I→R^n with k continuous derivatives; it is regular when γ′(t)≠0. A regular reparameterization is γ∘φ where φ is a C^k diffeomorphism between intervals. The result to establish is: Under an orientation-preserving reparameterization, tangent direction and all parameter-independent geometric quantities agree; an orientation-reversing change reverses the unit tangent. Read each component formula in a named parameter domain, chart, or frame, and distinguish the coordinate list from the geometric vector, form, metric, or curvature it represents.
The worked question is: For γ(t)=(cos 2t,sin 2t), 0<t<π, identify the traced set, speed, and orientation. Begin with “The identity x²+y²=1 shows that the trace lies on the unit circle, missing only the endpoint represented by t=0,π.” and finish with “At t=0 the velocity points upward, so the traversal is counterclockwise and covers one circuit.” Then compare with this nearby failure: The cusp γ(t)=(t²,t³) has γ′(0)=0, so its displayed trace does not provide a regular tangent through the origin. The comparison shows which part is coordinate-dependent and which conclusion survives every allowed change of coordinates.
Under an orientation-preserving reparameterization, tangent direction and all parameter-independent geometric quantities agree; an orientation-reversing change reverses the unit tangent.
Apply the chain rule: (γ∘φ)′(u)=γ′(φ(u))φ′(u).
Because φ′ never vanishes, regularity is preserved and the sign of φ′ records orientation.
Normalize the derivative; the positive scale cancels, while a negative scale contributes exactly one sign reversal.
For γ(t)=(cos 2t,sin 2t), 0<t<π, identify the traced set, speed, and orientation.
- The identity x²+y²=1 shows that the trace lies on the unit circle, missing only the endpoint represented by t=0,π.
- γ′(t)=(-2sin 2t,2cos 2t), so the speed is constantly 2 and never vanishes.
- At t=0 the velocity points upward, so the traversal is counterclockwise and covers one circuit.
Result: It is a regular counterclockwise unit-circle parameterization of speed 2 on the stated open interval.