Harmonic analysis asks how a function behaves across location, frequency, and scale
Objective: Which dilation would preserve the L² norm instead?
A single global frequency coefficient can detect oscillation but forget where it occurs. A local average detects location but smooths fine detail. Harmonic analysis organizes the trade between these descriptions and proves bounds that stay valid across all scales. Begin by naming the space, norm, scale, kernel, normalization, and equality or convergence sense. The chapter’s exact result is: Translation and modulation preserve every L^p norm, while ||D_af||_p=a^{-d(1−1/p)}||f||_p for 1≤p≤∞.
The precise object is: For f on R^d, translation is τ_yf(x)=f(x−y), L¹-normalized dilation is D_af(x)=a^{-d}f(x/a) for a>0, and modulation is M_ξf(x)=e^{iξ·x}f(x). Harmonic analysis compares location and frequency across scales; a picture of oscillations is evidence only after the operator and error notion are stated.
Use the exact problem “In dimension d=1, let f=1 on [0,1] and zero elsewhere. For a=2, find D_2f and its L¹ and L² norms.” to expose every constant and hypothesis. Rebuild the three steps, verify the result in a second representation, and test this failure boundary: Different dilation conventions preserve different quantities. Using an L¹-normalized formula while claiming L² energy preservation loses a factor a^{-d/2}.
Translation and modulation preserve every L^p norm, while ||D_af||_p=a^{-d(1−1/p)}||f||_p for 1≤p≤∞.
Translation uses u=x−y and Lebesgue-measure invariance; modulation has magnitude one.
For dilation, compute ∫|a^{-d}f(x/a)|^pdx and set u=x/a, so dx=a^ddu.
The p-th power norm gains a^{-dp+d}; taking the p-th root gives a^{-d(1−1/p)}, with the supremum case checked directly.
In dimension d=1, let f=1 on [0,1] and zero elsewhere. For a=2, find D_2f and its L¹ and L² norms.
- D_2f(x)=(1/2)f(x/2), so it equals 1/2 on [0,2] and zero elsewhere.
- Its L¹ norm is length 2 times height 1/2, equal to 1.
- Its squared L² norm is 2·(1/2)²=1/2, so ||D_2f||₂=1/√2.
Result: D_2f=(1/2)1_[0,2], with L¹ norm 1 and L² norm 1/√2.