A statement binds every variable to a universe
Objective: Why would ∃y∀x, x+y=0 say something stronger?
A formula becomes a truth-valued mathematical statement only after its free variables are assigned or quantified and its symbols receive an interpretation.
Objects and obligations: A variable occurrence is bound when it lies inside its quantifier’s scope; otherwise it is free. The result to establish is: For real x, x²≥0 is true, while x²≥0 with x free is an open formula rather than a complete proposition. Separate hypotheses from the target, bind every variable, and state whether the proof needs an arbitrary object, a witness, or a counterexample.
The worked question is: Close the formula x+y=0 so it states that every real x has an additive inverse. Start by “Declare x,y∈ℝ.” and close the argument with “Write ∀x∈ℝ ∃y∈ℝ, x+y=0.” Then compare the resulting proof obligation with this boundary: Changing the universe to complex numbers makes the order symbol ≥ undefined without extra structure.
For real x, x²≥0 is true, while x²≥0 with x free is an open formula rather than a complete proposition.
Declare the universe ℝ. This fixes the active universe, rule, or inference.
Bind x universally: ∀x∈ℝ, x²≥0.
Every real square is a product of equal-sign factors and is nonnegative.
Close the formula x+y=0 so it states that every real x has an additive inverse.
- Declare x,y∈ℝ. This verifies the stated construction or implication.
- Choose quantifier order ∀x∃y.
- Write ∀x∈ℝ ∃y∈ℝ, x+y=0.
Result: The closed statement is ∀x∈ℝ ∃y∈ℝ such that x+y=0.